9M 2015 passive income from non-REITs. | A Singaporean Stocks Investor (ASSI)
Hi AK saw your comment on buying Singtel at $3.66. Well done.
Do you usually sell a stock before XD and buy back on the XD date ?
9M 2015 passive income from non-REITs. | A Singaporean Stocks Investor (ASSI)
9M 2015 passive income from non-REITs. | A Singaporean Stocks Investor (ASSI)
Hi AK saw your comment on buying Singtel at $3.66. Well done.
Do you usually sell a stock before XD and buy back on the XD date ?
Hi AK saw your comment on buying Singtel at $3.66. Well done.
Do you usually sell a stock before XD and buy back on the XD date ?
Instructions
You have been invited to be one of the co-editors of this blog. Remember to sign in... Enter your response to the question as a Post (not under comments).
Colour of marbles chosen
journal writing on probability
A - SCORING AN 'A' FOR MATHS COMMON TEST
B - SCORING A 'C' FOR MATHS COMMON TEST
C - SCORING AN 'F' FOR MATHS COMMON TEST
EVENTS A, B AND C ARE MUTUALLY EXCLUSIVE EVENTS.
B - SCORING A 'C' FOR MATHS COMMON TEST
C - SCORING AN 'F' FOR MATHS COMMON TEST
EVENTS A, B AND C ARE MUTUALLY EXCLUSIVE EVENTS.
Possible Solution
In real life, the probability of me waking up late, having my breakfast slowly and strolling to the bus stop will then be adding the probability of each individual events.
Is this example ok?
Is this example ok?
Activity 7b
Let A be the event og geeting a 1 in the die, B the event of getting a 2 in the die and C be the event getting a 3. Hence, P(AUBUC) = P(A) + P(B) + P(C).
7B - Probability
In a golf tournament,
Let event A be the probability that Tiger Woods win. P(A) = 0.3
Let event B be the probability that Ernie Els win. P(B) = 0.2
Let event C be the probability that Vijay Singh win. P(C) = 0.1
Therefore, P(A U B U C) = P(A) + P(B) + P(C)
Let event A be the probability that Tiger Woods win. P(A) = 0.3
Let event B be the probability that Ernie Els win. P(B) = 0.2
Let event C be the probability that Vijay Singh win. P(C) = 0.1
Therefore, P(A U B U C) = P(A) + P(B) + P(C)
Cats, Chicken and Dogs are mutually exclusive
Event A = Cats give birth to kittens...
Event B = Chicken lay eggs....
Event C= Dogs give birth to puppies......
Everyone of them is mutually exclusive.
Therefore the probability of their union will have to be added individually bcos how each of them give birth to their young have got nothing to do with each other.
:D
Event B = Chicken lay eggs....
Event C= Dogs give birth to puppies......
Everyone of them is mutually exclusive.
Therefore the probability of their union will have to be added individually bcos how each of them give birth to their young have got nothing to do with each other.
:D
Of Ninjas, Pirates and Accountants.
Let's suppose we live in a world where the only thing we can be is either
(a) a ninja
(b) a pirate or
(c) an accountant
In this world, because all of these three roles are MUTUALLY EXCLUSIVE, there can never be a ninja-pirate or a ninja-accountant, pirate-accountant or that dreaded combination ninja-pirate-accountant from PWC. You can only be one of the three and nothing else.
Let's suppose the probability of being a ninja is 0.1 (taking into account that being a ninja is pretty tough with lots of training and hardwork). The probability of being a pirate is 0.8 (since everyone wants to be a pirate) and those people who can't hack being a pirate or a ninja becomes an accountant.
(a) a ninja
(b) a pirate or
(c) an accountant
In this world, because all of these three roles are MUTUALLY EXCLUSIVE, there can never be a ninja-pirate or a ninja-accountant, pirate-accountant or that dreaded combination ninja-pirate-accountant from PWC. You can only be one of the three and nothing else.
Let's suppose the probability of being a ninja is 0.1 (taking into account that being a ninja is pretty tough with lots of training and hardwork). The probability of being a pirate is 0.8 (since everyone wants to be a pirate) and those people who can't hack being a pirate or a ninja becomes an accountant.
Subscribe to:
Posts (Atom)